U: 400V
P: 15KW
Efficiency: 0,8 for a motor < 5KW
Efficiency: 0,9 for a motor > 5KW
Power factor: 0,8 for a motor < 5KW
Power factor: 0,9 for a motor > 5KW
V3 = 1,732

Nominal current absorbed by the motor:

I =               1500                   = 26,7 A
     ----------------------------
       400 x 1,732 x 0,9 x 0,9

The current rating of the relay must be 4 x I of the motor in order to withstand starting currents:
>>> 106,8 A >>> it's necessary to take a 125 A relay.